Methods from Second-order constant-coefficient equations
All methods from Second-order constant-coefficient equations.
Read the characteristic roots
Solve the characteristic equation and choose the real homogeneous modes according to the roots:
- If are distinct real roots, use
- If is a repeated real root, use
- If the roots are with , use
For a repeated root, and are independent; the factor is required. The extra mode comes from writing , where is the repeated root. Since and , substitution reduces the ODE to , so .
For a complex pair, controls exponential growth or decay and controls oscillation, as with the modulus and argument in polar form. For real coefficients, a non-real root always occurs with its complex conjugate. Since , its real and imaginary parts give the two real modes in the last row and the final solution needs no complex constants.
Undetermined coefficients
For suitable forcing functions:
- a polynomial of degree suggests a general polynomial of degree ;
- suggests ;
- suggests , where has degree ;
- or suggests
- or suggests
Substitute the trial into the equation and match coefficients. If the trial overlaps with a homogeneous mode whose characteristic root has multiplicity , multiply the whole trial by (so a simple overlap requires one factor of , while a repeated root requires ).
The trial families work because differentiating a polynomial, exponential or sinusoidal expression keeps it within the same finite-dimensional family, so substitution reduces the problem to algebraic coefficient matching. The correction accounts for resonance: a trial that already lies in the homogeneous solution space cannot produce the forcing after applying . Oscillation by itself is not resonance; resonance requires a forcing term whose trial shape overlaps a natural homogeneous mode.
Recover an IVP from an integral equation
Differentiate an integral equation with a variable limit, record the initial values obtained at the endpoint and solve the resulting differential equation subject to those values. Finally, check the original integral equation because differentiation can enlarge the solution set.