Threads
THCAL 2Ordinary differential equations
Write a linear equation as
L[y]=f(x),L[y]=ay′′+by′+cy.If yp is one particular solution and yh is any homogeneous solution, then the complete solution is
y=yh+yp.- 2Kernels and solution sets / constant-coefficient ODEs
MTCAL 2Ordinary differential equations
For suitable forcing functions:
- a polynomial of degree n suggests a general polynomial of degree n;
- eβx suggests Ceβx;
- pn(x)eβx suggests qn(x)eβx, where qn has degree n;
- sin(βx) or cos(βx) suggests C1cos(βx)+C2sin(βx);
- eαxsin(βx) or eαxcos(βx) suggests eαx(C1cos(βx)+C2sin(βx)).
Substitute the trial into the equation and match coefficients. If the trial overlaps with a homogeneous mode whose characteristic root has multiplicity s, multiply the whole trial by xs (so a simple overlap requires one factor of x, while a repeated root requires x2).
- 2Kernels and solution sets / finding a particular solution
DFCAL 2Ordinary differential equations
The kernel of a linear differential operator T is
ker(T)={y:T[y]=0}.- 2Kernels and solution sets / the kernel of a differential operator
THCAL 2Ordinary differential equations
If T[y]=f and yp is one particular solution, then
{all solutions of T[y]=f}=yp+ker(T).Equivalently, every solution is yp+yh for some homogeneous solution yh.
- 2Kernels and solution sets / linear differential equations
DFALG 3Linear transformations
If T:V→W is a linear map, its kernel is
ker(T)={u∈V:T(u)=0}.The same set is also called the null space. If A∈Fm×n is regarded as the map Fn→Fm, then
ker(A)={x∈Fn:Ax=0}.- 2Kernels and solution sets / the kernel
THALG 3Linear transformations
Let A be a matrix over an infinite scalar field F (such as R or C), let b be a vector of the appropriate dimension and let [A∣b] be the augmented matrix formed by appending b to A. The equation Ax=b has:
- no solution if rank(A)=rank([A∣b]);
- a unique solution if rank(A)=rank([A∣b])andnullity(A)=0;
- infinitely many solutions if rank(A)=rank([A∣b])andnullity(A)>0.
In the last case, if nullity(A)=k, then every solution has the form
x=xp+ω1u1+⋯+ωkuk,where xp is any particular solution of Ax=b, {u1,…,uk} is a basis for ker(A) and ω1,…,ωk∈F.
- 2Kernels and solution sets / matrix equations
2 / Algebra / Calculus / 6 stops
Every solution of T(x)=b is one particular solution plus an element of kerT.
- Within a chapter
- Waiting between chapters
- A stop
- One stop on two threads
- Pinned
- The thread in question