Examples from Reduction formulae
All examples from Reduction formulae.
[EXAMPLE]The recurrence with n=3, then n=2, then n=1 and I0=∫exdx, gives
I3=x3ex−3I2=x3ex−3(x2ex−2I1)=x3ex−3x2ex+6I1=x3ex−3x2ex+6(xex−I0)=x3ex−3x2ex+6xex−6∫exdx=x3ex−3x2ex+6xex−6ex+C.
[EXAMPLE]I5=54I3=54⋅32I1=158∫0π/2sinxdx=158[−cosx]0π/2=158.
[EXAMPLE]J7=76J5=76⋅54J3=3524⋅32J1=3516∫0π/2cosxdx=3516[sinx]0π/2=3516.
[EXAMPLE]The base value I2=∫0π/4sec2xdx=[tanx]0π/4=1 gives
∫0π/4sec4xdx=I4=31(2(4−2)/2+2I2)=31(2+2)=34.The base value J2=∫0π/4tan2xdx=∫0π/4(sec2x−1)dx=[tanx−x]0π/4=1−4π gives
∫0π/4tan4xdx=J4=31−J2=31−(1−4π)=4π−32.For mixed powers, K1=∫0π/4tanθsecθdθ=[secθ]0π/4=2−1, so
∫0π/4tan3θsecθdθ=K3=31(2−2K1)=31(2−2(2−1))=32−2.
[EXAMPLE]This is the definite version of the odd-power evaluation
of ∫cos5xsin4xdx. Reduce the cosine power twice, then the
sine power twice and use I1,0=1:
I5,4=94I3,4=94⋅72I1,4=638I1,4=638⋅53I1,2=1058I1,2=1058⋅31I1,0=3158.