Let V=C∞(R,R), the vector space of smooth real-valued
functions and let T:V→V be differentiation, T(f)=f′. For any real
λ, the function
f(x)=eλx
satisfies
T(f)=f′=λeλx=λf.
Thus eλx is an eigenvector of differentiation for the eigenvalue λ. For a matrix, the same test reads Av=λv, which is the form used throughout diagonalisation.
The two eigenspaces are perpendicular lines: A doubles the component
parallel to (1,1)T and removes the component parallel to
(1,−1)T. The roots 0 and 2 alone do not show this. The
eigenspaces are what describe the action of the matrix and supply an
eigenbasis.